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Binary Tree Inorder Traversal

Problem statement​

Given the root of a binary tree, return the inorder traversal of its nodes' values.

Example 1:

Input: root = [1,null,2,3]Output: [1,3,2]

Example 2:

Input: root = []Output: []

Example 3:

Input: root = [1]Output: [1]

Constraints:

  • The number of nodes in the tree is in the range [0, 100].
  • -100 <= Node.val <= 100
Follow up: Recursive solution is trivial, could you do it iteratively?

My solution​

/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {number[]}
 */
var inorderTraversal = function(root) {
    if (!root) {
        return []
    }
    
    const results = []
    
    function dfs(node) {
        if (!node) {
            return;
        }
        
        if (node.left) {
            dfs(node.left)
        }
        results.push(node.val)
        if (node.right) {
            dfs(node.right)
        }
    }
    
    dfs(root)
    
    return results
};