Skip to main content

Reverse Words in a String III

Problem statement​

Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:

Input: s = "Let's take LeetCode contest"Output: "s'teL ekat edoCteeL tsetnoc"

Example 2:

Input: s = "God Ding"Output: "doG gniD"

Constraints:

  • 1 <= s.length <= 5 * 104
  • s contains printable ASCII characters.
  • s does not contain any leading or trailing spaces.
  • There is at least one word in s.
  • All the words in s are separated by a single space.

My solution​

/**
 * @param {string} s
 * @return {string}
 */
var reverseWords = function(s) {
    // console.log(s.split(/\s/))
    return s.split(/\s/).map((v) => reverseString(v.split(""))).join(" ")
};

var reverseString = function(s) {    
    for (let i = 0; i < Math.floor(s.length / 2); i++) {
        const j = s.length - 1 - i;
        
        [s[j], s[i]] = [s[i], s[j]]
    }
    return s.join("")
};