Flipping an Image

Problem statement

Given an n x n binary matrix image, flip the image horizontally, then invert it, and return the resulting image.

To flip an image horizontally means that each row of the image is reversed.

• For example, flipping [1,1,0] horizontally results in [0,1,1].

To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0.

• For example, inverting [0,1,1] results in [1,0,0].

Example 1:

Input: image = [[1,1,0],[1,0,1],[0,0,0]]Output: [[1,0,0],[0,1,0],[1,1,1]]Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]

Example 2:

Input: image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]

Constraints:

• n == image.length
• n == image[i].length
• 1 <= n <= 20
• images[i][j] is either 0 or 1.

My solution

/**
 * @param {number[][]} image
 * @return {number[][]}
 */
var flipAndInvertImage = function(image) {
    for (let i = 0; i < image.length; i++) {
        image[i] = reverse(image[i])
    }
    
    for (let i = 0; i < image.length; i++) {
        for (let j = 0; j < image[0].length; j++) {
            if (image[i][j] === 0) {
                image[i][j] = 1
            } else {
                image[i][j] = 0
            }
        }
    }
    
    function reverse(arr) {
        for (let i = 0; i < arr.length / 2; i++) {
            [arr[i], arr[arr.length - 1 - i]] = [arr[arr.length - 1 - i], arr[i]]
        }
        return arr;
    }
    
    return image
};