Top K Frequent Elements
Problem statement
Given an integer array nums and an integer k, return the k most frequent elements. You may return the answer in any order.
Example 1:
Input: nums = [1,1,1,2,2,3], k = 2Output: [1,2]
Example 2:
Input: nums = [1], k = 1Output: [1]
Constraints:
1 <= nums.length <= 105kis in the range[1, the number of unique elements in the array].- It is guaranteed that the answer is unique.
Follow up: Your algorithm's time complexity must be better than O(n log n), where n is the array's size.
My solution
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
var topKFrequent = function(nums, k) {
const memo = new Map();
for (const num of nums) {
memo.set(num, (memo.get(num) || 0) + 1)
}
const result = [...memo].sort((a, b) => b[1] - a[1])
// console.log(result)
return result.slice(0, k).map(([key]) => key)
};