Reorder Data in Log Files

Problem statement

You are given an array of logs. Each log is a space-delimited string of words, where the first word is the identifier.

There are two types of logs:

• Letter-logs: All words (except the identifier) consist of lowercase English letters.
• Digit-logs: All words (except the identifier) consist of digits.

Reorder these logs so that:

1. The letter-logs come before all digit-logs.
2. The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.
3. The digit-logs maintain their relative ordering.

Return the final order of the logs.

Example 1:

Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]Explanation:The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".

Example 2:

Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]

Constraints:

• 1 <= logs.length <= 100
• 3 <= logs[i].length <= 100
• All the tokens of logs[i] are separated by a single space.
• logs[i] is guaranteed to have an identifier and at least one word after the identifier.

My solution

/**
 * @param {string[]} logs
 * @return {string[]}
 */
var reorderLogFiles = function(logs) {
    const letterLogs = logs.filter(log => {
        return log.match(/^[a-z0-9]+\s(?!\d)/)
    }).sort((a, b) => {
        const [_, idA, strA] = a.match(/^([a-z0-9]+)\s(.+)/)
        const [__, idB, strB] = b.match(/^([a-z0-9]+)\s(.+)/)
        
// localeCompare => 0 if they are equivalent.
        // console.log(idA, idB, parseInt(idA), parseInt(idB))
        if (strA.localeCompare(strB) === 0) {
            return idA.localeCompare(idB)
        }
        
        return strA.localeCompare(strB)
    })
    const digitLogs = logs.filter(log => {
        return !log.match(/^[a-z0-9]+\s(?!\d)/)
    })
    
    return [
        ...letterLogs,
        ...digitLogs
    ]
};