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Sort Array By Parity

Problem statement​

Given an integer array nums, move all the even integers at the beginning of the array followed by all the odd integers.

Return any array that satisfies this condition.

Example 1:

Input: nums = [3,1,2,4]Output: [2,4,3,1]Explanation: The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.

Example 2:

Input: nums = [0]Output: [0]

Constraints:

  • 1 <= nums.length <= 5000
  • 0 <= nums[i] <= 5000

My solution​

/**
 * @param {number[]} nums
 * @return {number[]}
 */
var sortArrayByParity = function(nums) {
    return [...nums.filter(v => v % 2 === 0), ...nums.filter(v => v % 2 !== 0)]
};