Word Pattern
Problem statement
Given a pattern and a string s, find if s follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in s.
Example 1:
Input: pattern = "abba", s = "dog cat cat dog"Output: true
Example 2:
Input: pattern = "abba", s = "dog cat cat fish"Output: false
Example 3:
Input: pattern = "aaaa", s = "dog cat cat dog"Output: false
Constraints:
1 <= pattern.length <= 300patterncontains only lower-case English letters.1 <= s.length <= 3000scontains only lowercase English letters and spaces' '.sdoes not contain any leading or trailing spaces.- All the words in
sare separated by a single space.
My solution
/**
* @param {string} pattern
* @param {string} s
* @return {boolean}
*/
var wordPattern = function(pattern, s) {
const memo = new Map();
const seenWord = new Set();
const sArr = s.split(/\W/)
for (const mat of pattern) {
const word = sArr.shift()
// console.log(word)
if (word !== undefined && !memo.has(mat) && !seenWord.has(word)) {
memo.set(mat, word)
seenWord.add(word)
} else if (memo.get(mat) !== word || word === undefined) {
return false;
}
}
console.log(memo, seenWord)
if (sArr.length) {
return false
}
return true
};