Height Checker

Problem statement

A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array expected where expected[i] is the expected height of the ith student in line.

You are given an integer array heights representing the current order that the students are standing in. Each heights[i] is the height of the ith student in line (0-indexed).

Return the number of indices where heights[i] != expected[i].

Example 1:

Input: heights = [1,1,4,2,1,3]Output: 3Explanation: heights:  [1,1,4,2,1,3]expected: [1,1,1,2,3,4]Indices 2, 4, and 5 do not match.

Example 2:

Input: heights = [5,1,2,3,4]Output: 5Explanation:heights:  [5,1,2,3,4]expected: [1,2,3,4,5]All indices do not match.

Example 3:

Input: heights = [1,2,3,4,5]Output: 0Explanation:heights:  [1,2,3,4,5]expected: [1,2,3,4,5]All indices match.

Constraints:

• 1 <= heights.length <= 100
• 1 <= heights[i] <= 100

My solution

/**
 * @param {number[]} heights
 * @return {number}
 */
var heightChecker = function(heights) {
    const sorted = [...heights].sort((a, b) => a - b);
    
    let count = 0;
    // console.log(sorted)
    for(let i = 0; i < heights.length; i++) {
        // console.log(heights[i], sorted[i]);
        if (heights[i] !== sorted[i]) {
            count++
        }
    }
    
    return count;
};