Skip to main content

Palindrome Number

Problem statement

Given an integer x, return true if x is palindrome integer.

An integer is a palindrome when it reads the same backward as forward.

  • For example, 121 is a palindrome while 123 is not.

Example 1:

Input: x = 121Output: trueExplanation: 121 reads as 121 from left to right and from right to left.

Example 2:

Input: x = -121Output: falseExplanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.

Example 3:

Input: x = 10Output: falseExplanation: Reads 01 from right to left. Therefore it is not a palindrome.

Constraints:

  • -231 <= x <= 231 - 1
Follow up: Could you solve it without converting the integer to a string?

My solution

/**
* @param {number} x
* @return {boolean}
*/
var isPalindrome = function(x) {
if (x < 0 || (x!== 0 && x % 10 === 0)) {
return false;
}

let nums = x;
let reverse = 0;

while (nums) {
// console.log("nums", nums)
reverse = (reverse * 10) + (nums % 10);
nums = Math.floor(nums / 10);
}


return x === reverse
};